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-3x^2+15x+16=0
a = -3; b = 15; c = +16;
Δ = b2-4ac
Δ = 152-4·(-3)·16
Δ = 417
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{417}}{2*-3}=\frac{-15-\sqrt{417}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{417}}{2*-3}=\frac{-15+\sqrt{417}}{-6} $
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